Question

需要能够做一个循环, 做类似的事情:

第一次通过环绕 :

for(int i=0;i<5;i++)
{
    example.print(0);
}

第二次通过:

for(int i=0;i<5;i++)
{
    example.print(0);
    example.print(1);
}

以其他示例为例。打印( ) 每一次都添加。

In order for the program to work correctly, each "example.print()" has to physically be there is the code. Any ideas?

Answer 1

听起来你想要嵌套环:

for (int i = 0; i < 5; i++) {
    for (int j = 0; j < 5; j++) {
        example.print(i + j); // This will need adjusting
    }
}

注:

You ll want to adjust the i + j part as necessary to get the desired output. You didn t say what should happen when we got past the first five. :-)
You didn t say how many passes you wanted, so I assumed 5. If you want fewer, change the upper limit of the i loop (the outer one), probably.

Answer 2

int loopCounter = 0;

for(int i=0;i<5;i++)
{
    for(int k=0; k<loopCounter; k++)example.print(k);
    loopCounter++;
}

Answer 3

我的版本:

for(int i=0;i<5;i++)
{
    for(int k=0; k<i; k++)
          example.print(k);
}

Answer 4

试试这个

for (int x = 0,y = 0; x < 100; x++,y++) {

        example.print(x + y); // You will need to tweak these values
    }

100是这里的假设值, 因为圆圈会反复循环的时数。

Answer 5

此处为我的拍摄, * 考虑您发送到打印方法的参数, 是您想要打印的参数。

int n=3; //n is the highest param value you want your print method to receive, 
         //here it s just 3

for (int i=0; i<n; i++) {
    for (int j=0; j<(i+1)*5; j++) {
        example.print(j/5);
    }
}

Answer 6

谁都能猜到你"身体上"是什么意思但我会试一试

final Example example = new Example();
for (int i = 0; i < 5; i++)
  switch (i) {
    case 4: example.print(i-4);
    case 3: example.print(i-3);
    case 2: example.print(i-2);
    case 1: example.print(i-1);
    case 0: example.print(i-0);
  }

友情链接