http://support.microsoft.com/kb/316920
我相信那篇文章会解释你为什么会有问题, 它提供了解决问题的解决方案。
我知道你不想使用回应。 调整方向, 但我认为这也解决了问题。
PRB: "View State Is Invalid" Error Message When You Use Server.Transfer
这篇文章以前在Q316920中发表
Retired KB Content Disclaimer
This article was written about products for which Microsoft no longer
offers support. Therefore, this article is offered "as is" and will no
longer be updated.
SYMPTOMS
When you use HttpServerUtility.Transfer("page name", true), you
receive the following error message:
查看国对本页面无效, 并可能损坏
CAUSE
This problem occurs because the EnableViewStateMac attribute of the
<pages> element is set to true by default. When this attribute is
set to true, ASP.NET runs a message authentication check (MAC) on the
view state of the page when the page is posted back from the client.
This check determines if the view state of the page was modified on
the client. For security purposes, it is recommended that you keep
this attribute set to true.
When you call the Server.Transfer method and set the second
parameter to true, you preserve the QueryString and the Form
collections. One of the form fields is the hidden __VIEWSTATE form
field, which holds the view state for the page. The view state message
authentication check fails because the message authentication check
only checks each page. Therefore, the view state from the page that
calls Server.Transfer is not valid on the destination page.
View state is page scoped and is valid for that page only. View state
should not be transferred across pages.
RESOLUTION
为解决这一问题,应采用以下方法之一。
Resolution 1
Transfer values between pages to pass your server control values to
the other pages. For more information, refer to the following MSDN
documentation: Passing Server Control Values Between
Pages
This requires that you create public properties for each property of a
control that you want to access from the destination page.
If you have many controls, and if you want to access the properties of
these controls from another page, you can also declare those controls
as public variables. For example:
< 强 > page1.aspx
Public Class Page1
Public WithEvents TextBox1 As System.Web.UI.WebControls.TextBox
Insert your code here.
End Class
<强 > page2.aspx
Dim sourcePage As Page1
sourcePage = CType(Context.Handler, WebForm1)
Response.Write(sourcePage.TextBox1.Text)
Resolution 2
Do not pass the second parameter (which is false by default) when
you call Server.Transfer. For example:
Server.Transfer("<page name>")
This code does not send the QueryString and the Form fields to the
page that is called. When no data is transferred, ASP.NET does not run
the message authentication check.
MORE INFORMATION
Steps to Reproduce the Behavior
创建名为 WebForm1.aspx 的.aspx 页面, 将执行传输到另一页。 添加以下代码到 WebForm1.aspx :
<%@ Page language="vb" AutoEventWireup="true" %>
<html>
<body>
<form id="WebForm1" method="post" runat="server">
<asp:TextBox id="txtName" runat="server">Your Name</asp:TextBox><br>
<asp:Button id="Button1" runat="server" Text="Submit" OnClick="Button1_Click"></asp:Button>
</form>
</body>
</html>
<script runat=server>
Sub Button1_Click(sender As Object, e As System.EventArgs)
Server.Transfer("WebForm2.aspx",true)
End Sub
</script>
另创建名为 WebForm2.aspx 的.aspx 页面, 然后添加以下代码 :
<%@ Page language="vb" AutoEventWireup="true" %>
<html>
<body>
<form id="WebForm2" method="post" runat="server">
<asp:Label id="lblName" runat="server" >Web Form 2</asp:Label>
</form>
</body>
</html>
<script runat=server>
Sub Page_Load(sender As Object, e As EventArgs)
Dim thisPage As System.Web.UI.Page
Dim nameTextBox As TextBox
thisPage = CType(Context.Handler, System.Web.UI.Page)
nameTextBox = CType(thisPage.FindControl("txtName"), System.Web.UI.Control)
lblName.Text = "Your name is " & nameTextBox.Text & " ."
End Sub
</script>
在浏览器中打开 WebForm1.aspx, 然后单击 < 坚固> submit 。
