如何转换以下字符串 :
24 May, 2012, 00:00am
格式化为 :
$today = date("D M j G:i:s T Y"); // Sat Mar 10 17:16:18 MST 2001
我尝试过以下方法:
$date = date( D M j G:i:s T Y , strtotime("24 May, 2012, 00:00am"));
但我得到的只有:
Thu Jan 1 0:00:00 UTC 1970
我正在考虑引爆绳子,然后通过“http://php.net/manual/en/formation.mktime.php” rel=“nofollow”
我会使用"http://www.php.net/manual/en/class.datetime.php" rel="noreferrer"\ code >DateTime 类和CrecompateFroformat 函数,允许您按照您定义的格式分析日期。
在这种情况下:
$date = DateTime::createFromFormat("d M, Y, h:ia", "24 May, 2012, 00:00am");
然后您可以使用其他 DateTime 函数来操作此功能。
请注意,您提供的日期实际上不正确, 任何标准 : 您指的是 < code> 00: 00 或 < code> 12: 00 am 。
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