Question

您如何在 Go 中将一长串数字( 50 位数) 转换成整数?

下面是代码的输出:

number = 2147483647

err = strconv.ParseInt: parsing "37107287533902102798797998220837590246510135740250 ": value out of range

它似乎只能转换最多达2147483647的数字。

package main

import "fmt"
import "io/ioutil"
import "strings"
import "strconv"

var (
        number int64
)

func main() {
    fData,err := ioutil.ReadFile("one-hundred_50.txt")
    if err != nil {
            fmt.Println("Err is ",err)
        }   
    strbuffer := string(fData)
    lines := strings.Split(strbuffer, "
")

    for i, line := range lines {
        fmt.Printf("%d: %s
", i, line)
        number, err := strconv.Atoi(line)
        fmt.Println("number = ", number)
        fmt.Println("err = ", err)
    }   
}

Answer 1

您想要 < a href=> " "http://golang.org/pkg/math/big" >math/big 软件包, 提供任意精度整数支持。

import "math/big"

func main() {
    // ...
    for i, line := range lines {
        bi := big.NewInt(0)
        if _, ok := bi.SetString(line, 10); ok {
            fmt.Printf("number = %v
", bi)
        } else {
            fmt.Printf("couldn t interpret line %#v
", line)
        }
    }
}

这里有",http://play.golang.org/p/izWUY9WwY"。

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