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Geopy 例外处理
原标题:Geopy exception handling

Traceback (most recent call last):
File "C:UsersPenguinworkspacegeocode-nojansdatabasesrcgeocode.py", line 15, in
place, (lat, lng) = g.geocode(a)
File "C:Python27libsite-packagesgeopy-0.94.2-py2.7.egggeopygeocodersgoogle.py", line 81, in geocode
return self.geocode_url(url, exactly_one)
File "C:Python27libsite-packagesgeopy-0.94.2-py2.7.egggeopygeocodersgoogle.py", line 88, in geocode_url
return dispatch(page, exactly_one)
File "C:Python27libsite-packagesgeopy-0.94.2-py2.7.egggeopygeocodersgoogle.py", line 111, in parse_xml
"(Found %d.)" % len(places))
ValueError: Didn t find exactly one placemark! (Found 3.)

当 Geopy 遇到一个地址时, 它不喜欢我的应用程序终止 。 我想知道的是, 我怎样才能在 Python 中捕捉例外, 并允许我的程序转到下一个条目 。 源代码如下 :

import csv
from geopy import geocoders
import time

g = geocoders.Google()

spamReader = csv.reader(open( locations.csv ,  rb ), delimiter= 	 , quotechar= | )

f = open("output.txt", w )

for row in spamReader:
     a =  ,  .join(row)
     #exactly_one = False
     time.sleep(1)
     place, (lat, lng) = g.geocode(a)
     b = """ + str(place) + """ + "," + str(lat) + "," + str(lng) + "
"
     print b
     f.write(b)
最佳回答

要让您的程序忽略价值错误, 而不是终止它, 则通过替换 :

 place, (lat, lng) = g.geocode(a)

与:

 try:
     place, (lat, lng) = g.geocode(a)
 except ValueError:
     continue

( continue 使得它进入循环的下一个重复, 而不是试图执行当前循环的其余部分---- 这似乎是正确的事情, 因为当前循环的其余部分取决于位置, lat, lng) 。

或者,如果你想用它打印信息,请使用

 try:
     place, (lat, lng) = g.geocode(a)
 except ValueError as error_message:
     print("Error: geocode failed on input %s with message %s"%(a, error_message))
     continue

或沿着这条线的某样东西。

问题回答

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