据我所知,“强”后背线 连接队列的大小。 任何额外请求如果在当时的大小更大, 将会被删除( 是否正确? )。
现在我有非常简单的程序server.c
socket()
bind()
listen(..., 5)
while(1)
{
accept()
read()
write()
sleep(3)
close()
}
现在, 我开始使用 8 个客户端 < 坚固 > 的时间 < / 坚固 > 连接到此服务器 。 令人惊讶的是, 服务器为所有 8 个客户服务, 但它应该只排队 5 个客户 & amp ; 其余 3 个客户端请求应该被拒绝 。 另一个有趣的一点是, 即使我把这个积压值定为 0, 结果还是一样 。 然后, 我试图评论听( ) 电话, 而这8 个客户端的连接都被拒绝 。
有人能对此提供任何投入吗?
积压的参数是有关队列大小的 int 。 所以您不能指望它来做您要做的事 。
这 < a href=""https://stackoverflow.com/ questions/511040/lisen-ignores-the-backlog-argument" > 回答 似乎涵盖了这个问题。
我Ubuntu系统上的监听(2)主页引用了更多信息:
The backlog argument defines the maximum length to which the queue of pending connections for sockfd may grow. If a connection request arrives when the queue is full, the client may receive an error with an indication of ECONNREFUSED or, if the underlying protocol supports retransmission, the request may be ignored so that a later reattempt at connection succeeds.
注意上面到处写着"可以"
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