所以我想找到一个方法 在一个美丽的 Soup 对象中找到所有的项目, 如果该对象有一定的标签, 而不在某个其它标签中。例如:
<td class="disabled first"> <div class="dayContainer">
<p class="day"> 29
</p> <p class="moreLink">
</p>
</div>
</td>
我想找到所有 class="day Container" 的迭代, 这很简单, 但我要如何找到所有在 class="diabled" 中不是首选的?
运行一个过滤器, 用于那些. 父母没有该类属性的标签 。 类似
filteredDayContainers = [tag for tag in soup.find_all( div ,
attrs = { class : dayContainer })
if "disabled" not in tag.parent[ class ]]
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