Question

我下载了我的JQuery Mobile 应用程序的文件结构。我这样做是为了从本地文件系统测试它运行。为什么我要我的应用程序与Cordova一起运行。我的理解线索洛娃在文件 @ 。目前, 我的文件结构是这样的 :

index.html
account
  register.html
  reset.html

在索引. html中, 我有一个“ 签名” 按钮。当有人点击时, 我使用以下代码 :

$.mobile.changePage("account/register.html", { transition: "slide" });

我验证过这个登记簿. html 如果将完整路径放入浏览器 URL, 工作会顺利。奇怪的是, 我点击“ 签名” 时会看到“ 错误加载页面 ” 。文件 / 下使用更改页面是否有问题。如果有问题, 我如何克服?

谢谢!

Answer 1

试这个

$.mobile.changePage("../account/register.html", { transition: "slide" });

Answer 2

您可以在代码中保留时间：2012-05-28 08:27:31

如果您遇到在iOS上运行 PhoneGap 应用程序的问题, 此答案是具体的。

请确定您设置 AJAX 呼叫输入页面所需的 $.move.allowCrossDomainPages = true; 。

在您的 PhoneGap app 对象定义中:

var app = {
    initialize: function() {
        // setting required to use $.mobile.changePage()
        // http://jquerymobile.com/demos/1.2.0/docs/pages/phonegap.html
        $.mobile.allowCrossDomainPages = true;
    },
};

所以当您在您的 index.html 中调用 app. reliminization () 时, 此属性将在任何 $.move.changePage () 函数调用之前设定。

这将节省你数小时试图找出问题,因为没有错误通过Safari Web检查员返回。

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Answer 3

如果您遇到在iOS上运行 PhoneGap 应用程序的问题, 此答案是具体的。

请确定您设置 AJAX 呼叫输入页面所需的 $.move.allowCrossDomainPages = true; 。

在您的 PhoneGap app 对象定义中:

var app = {
    initialize: function() {
        // setting required to use $.mobile.changePage()
        // http://jquerymobile.com/demos/1.2.0/docs/pages/phonegap.html
        $.mobile.allowCrossDomainPages = true;
    },
};

所以当您在您的 index.html 中调用 app. reliminization () 时, 此属性将在任何 $.move.changePage () 函数调用之前设定。

这将节省你数小时试图找出问题,因为没有错误通过Safari Web检查员返回。

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