我与使用空格作为千位分隔符的文本合作, 例如 400 或 40 000 或 40 000 000 或 40 000 000 或 4 000 000 000 。 我需要识别字符串中的数字。 一旦识别, 有很多选项可以重新格式化数字 。 在正则上我是一个菜鸟。 这不起作用 :
import re
line = 40) He had 120 hours to increase from 40 000 units to 20 000 000.
regex = re.compile("(d+ *d+)")
re.findall(regex, line)
[ 40 , 120 , 40 000 , 20 000 , 000 ]
将开展以下工作:
regex = re.compile(r"(d+(?:s+d+)*)")
这使用一个非捕获组 (? :) , 匹配一个或多个空格( > =%/code > ) 的 < code > ( \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
值得指出的是,对 Python 常规表达式使用原始字符串( r" " 或 r )通常是一个好主意。
最后,我可能要像这样收紧正谱
regex = re.compile(r"(d+(?:s+d{3})*)")
这就要求除第一个数字外,每一组数字的长度为3位数。
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