Question

I have a Python module with a function in it:

  == bar.py ==
  def foo(): pass
  == EOF ==

And then I import it into the global namespace like so:

from bar import *

So now the function foo is available to me. If I print it:

print foo

The interpreter happily tells me:

 <function foo at 0xb7eef10c>

Is there a way for me to find out that function foo came from module bar at this point?

Answer 1

foo.__module__ should return bar

If you need more info, you can get it from sys.modules[ bar ], its __file__ and __package__ attributes may be interesting.

Answer 2

Try this:

help(foo.func_name)

Answer 3

Instead of

from bar import *

use

from bar import foo

Using the from ... import * syntax is a bad programming style precisely because it makes it hard to know where elements of your namespace come from.

Answer 4

If you have IPython, you can also use ?:

In[16]: runfile?
Signature: runfile(filename, args=None, wdir=None, is_module=False, global_vars=None)
Docstring:
Run filename
args: command line arguments (string)
wdir: working directory
File:      /Applications/PyCharm.app/Contents/helpers/pydev/_pydev_bundle/pydev_umd.py
Type:      function

Compare with __module__:

In[17]:  runfile.__module__
Out[17]:  _pydev_bundle.pydev_umd

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