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Why I can t pass two chars as function arguments in C?
原标题:

I have a function:

int get_symbol(tab *tp, FILE *fp, char delim)

and I call it like this:

get_symbol(tp, fp,  ; )

I always have it declared in the header as:

int get_symbol(tab *, FILE *, char);

No this all works fine, I can execute the code in the function and the delim is set. But if I try to add one more char to the function s signature like:

int get_symbol(tab *tp, FILE *fp, char delim1, char delim2)

The function stops executing. Why would that be?

问题回答

You should have :

int get_symbol(tab *tp, FILE *fp, char delim1, char delim2)
{
blah blah;
return 1;
}
...
...

get_symbol(tp, fp,  ; , ? )

do You?

OK, there s not enough information here, so I m going to make a wild stab at an answer.

You re using a C++ compiler, and don t have warning levels set very high. You ve changed the prototype for the function, but you ve not changed the arguments when you call it. The C++ compiler is treating these as different functions due to overloading, and so is not calling the right one.

This may be way off what s happening. If it is, give us something more to go on….

As a guess at what "stops executing" could mean, did you update the signature in the header file as well?





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