Below is my rule, when i replace $2 with = my code works. I know by default all literal tokens uses their ascii value (hence why multi character token require a definition)
The below doesnt work. The function is called with 0 instead of = like i expect. is there an option i can set? (It doesn t appear so via man pages)
AssignExpr: var = rval { $$ = func($1, $2, $3); }
In another piece of code i have MathOp: = | + | % ... hence why i am interested.
The value for $2 in this context will be whatever the yylex function put into the global variable yylval before it returned the token = . If the lexer doesn t put anything into yylval, it will probably still be 0, as you re seeing.
I think you are right, Bison just doesn t work that way.
You can easily fix it, of course:
=, recognize it in your lexer, and return its semantic value, or...$$
or...If I just add on to the following yacc file, will it turn into a parser? /* C-Minus BNF Grammar */ %token ELSE %token IF %token INT %token RETURN %token VOID %token WHILE %token ID %token NUM %...
Is it always necessary to do so? What does it look like?
Is it true that in the following file, INT is taken literally, while ID is not? How can you tell? /* C-Minus BNF Grammar */ %token ELSE %token IF %token INT %token RETURN %token VOID %token WHILE %...
Below is my rule, when i replace $2 with = my code works. I know by default all literal tokens uses their ascii value (hence why multi character token require a definition) The below doesnt work. ...
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