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CGWindowID from AXUIElement
原标题:

I m trying to automate a foreign OSX application using the accessibility API. Some of the state of the application isn t available through the API, so I acquire it through screen scraping. To do this, I need to get CGWindowID for an accessibility object with a Window Role .

Is there any direct way of acquiring CGWindowID of a Window Role accessibility object? I can get it heuristically, by matching various attributes of the window, such as the size, title and location, but this is really hacky, and I d feel better if my application would also support the corner cases, even if they are unlikely.

最佳回答

There’s no way to do that; the accessibility hierarchy is completely decoupled from the actual window/view hierarchy. I think your matching will work best.

问题回答

There is a function from at least Leopard and up (and still around as of 10.7.3):

extern "C" AXError _AXUIElementGetWindow(AXUIElementRef, CGWindowID* out);

Usual caveats about using something like this apply though. It may change as soon as the next OS update!

The correct current declaration in a Swift Bridging Header is:

#import <AppKit/AppKit.h>

AXError _AXUIElementGetWindow(AXUIElementRef element, uint32_t *identifier);

As used here: https://github.com/rxhanson/Rectangle/blob/master/Rectangle/Rectangle-Bridging-Header.h





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