Question

>>> sum((1, 2, 3, 4, 5, 6, 7))
28
>>> 28/7
4.0
>>> sum((1,2,3,4,5,6,7,8,9,10,11,12,13,14))
105
>>> 105/7
15.0
>>>

How do I automate this sum and division using a loop maybe?

Edit: Maybe I wasn t clear - I want a loop to keep doing the sum (of multiples of 7, eg 1-7, 1-14, 1-21 etc..) until it reaches x (x is the user input)

Okay, figured it out:

def sum_and_div_of_multiples_of_7(x):
  y = 7
  while (y <= x):
    mof7 = range(1,y)
    print ( mof7 is , mof7)

    total = sum(mof7)
    print ( total = , total)

    div = total/7
    print ( div = , int(div),  
 )

    y = y+7     # increase y

x = 70
sum_and_div_of_multiples_of_7(x)

Answer 1

def sumdiv7(limit):
    for i in range(limit):
        result = sum(range(i*7)) / 7
        print "For", i, ", sumdiv = ", result

Example:

>>> sumdiv7(4)
For 0 , sumdiv =  0
For 1 , sumdiv =  3
For 2 , sumdiv =  13
For 3 , sumdiv =  30

The trick is very simple, you want to sum multiples of 7,

To get the ith multiple of 7, it s just i*7

range is a python function to get a list of numbers from 0 to x

sum sums a list.

Just put these pieces together

Answer 2

The direct answer:

def sum_to_number_divided_by_seven(i):
  return sum(range(i+1)) / 7

The more efficient answer:

def sum_to_number_divided_by_seven(i):
  return (i*(i+1))/14

Answer 3

I m not sure what you want, but maybe it is something like:

sum(range(x*7+1))/7

Answer 4

My version:

def sum_of_nums_divided_by_7(num):
    return reduce(lambda x, y: x+y, range(num)) / 7

Answer 5

if i understand your problem correctly. You want to be able to accept user input - x, and then sum values 1-7 then devide by 7, if the qoutient is higher than x stop there, otherwise continue to sum up 1-14, devide by 7 and check that quotient - and continute in multiples of 7?

My easy sollution is

x = input( user input - enter your value here )
y = 0
i = 1
while(x > y):
    q = sum(range(1, i*7+1))
    y = q/7
    print y
    i+=1

print "userinput:  %d" % (x)
print "iterations:  %d" %(i)
print "end value: %d" %(y)

友情链接