i want to execute a sql at php which does something like changing a text column into int column.
however, this sql failed to fun at php and succeeds in my mysql admin tool (sqlyog). server responses "1 row(s) affected. 1 warning(s)". but "SHOW WARNINGS" didn t pop up anything and not surprisingly, php s mysql_error() didn t return anything.
thanks.
The best is to use the mysqli extension instead of the old mysql extension, as mysqli supports all of MySQL s features and offers the mysqli_get_Warnings() function. Without mysqli you can do mysql_query("SHOW WARNINGS"); (see SHOW WARNINGS docs) and then read the warnings from the result set.
I noticed that there were some threads with similar questions, and I did look through them but did not really get a convincing answer. Here s my question: The subquery below returns a Table with 3 ...
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