I think of this as a two-step process:
subset the original data frame according to the filter supplied
(Believe==FALSE); then
get the row count of this subset
For the first step, the subset function is a good way to do this (just an alternative to ordinary index or bracket notation).
For the second step, i would use dim or nrow
One advantage of using subset: you don t have to parse the result it returns to get the result you need--just call nrow on it directly.
so in your case:
v = nrow(subset(Santa, Believe==FALSE)) # subset returns a data.frame
or wrapped in an anonymous function:
>> fnx = function(fac, lev){nrow(subset(Santa, fac==lev))}
>> fnx(Believe, TRUE)
3
Aside from nrow, dim will also do the job. This function returns the dimensions of a data frame (rows, cols) so you just need to supply the appropriate index to access the number of rows:
v = dim(subset(Santa, Believe==FALSE))[1]
An answer to the OP posted before this one shows the use of a contingency table. I don t like that approach for the general problem as recited in the OP. Here s the reason. Granted, the general problem of how many rows in this data frame have value x in column C? can be answered using a contingency table as well as using a "filtering" scheme (as in my answer here). If you want row counts for all values for a given factor variable (column) then a contingency table (via calling table and passing in the column(s) of interest) is the most sensible solution; however, the OP asks for the count of a particular value in a factor variable, not counts across all values. Aside from the performance hit (might be big, might be trivial, just depends on the size of the data frame and the processing pipeline context in which this function resides). And of course once the result from the call to table is returned, you still have to parse from that result just the count that you want.
So that s why, to me, this is a filtering rather than a cross-tab problem.