Question

while (curr_data[1] != (unsigned int)NULL &&
    ((curr_ptr = (void*)curr_data[1]) || 1))

两个部分问题。

(curr_ptr = (ave*)curr_data***)在逻辑上评价。 http://www.un.org。

而且,我知道它只是 ha,但while statement legal C? 我不得不通过大的调子来把《守则》其他地方的任务放在一边,因此,如果我能够离开,我真的是 n,但如果它如此奇怪,它使每个人的眼球陷入火焰,我就会改变。

Answer 1

回答你的问题:

It will evaluate to true if curr_ptr isn t set to NULL (i.e. curr_data[1] isn t 0).
I believe it s legal, but there are bigger problems with this line of code.

不管怎么说,我假定你没有写这本法典,因为你在把它删除时重新辩论。因此,我希望你发现,谁写了这条法典,并将其引入一个 heavy强的物体。

(unsigned int)NULL is ridiculous. Why would you do this? This will probably be the same as just writing 0 (not sure if that s guaranteed by the standard).
What kind of data is in curr_data[1] if it s being cast to a pointer (and pointers are being cast to it)? If it s supposed to be holding a pointer as an integral type, you should use the type intptr_t or uintptr_t provided in <stdint.h> for that purpose (if you re compiler doesn t support C99 ptrdiff_t may be an acceptable substitute).
The || 1 at the end seems to be redundant. If curr_ptr = (void*)curr_data[1] would have evaluated to false, we would have caught that in the first condition.

这可能是痛苦的,但认真重新审议这一行文。它喜欢加入国际奥委会。

Answer 2

(curr_ptr = (ave*)curr_data? >将评价西非法郎,除非它是一个无效点。

假设<代码>curr_data是一系列点数,而你想要的是操作该方位,而其中第二位点位数并不完全无效,同时将其价值分配给<代码>curr_ptr<>/code>,我将:

while ((curr_ptr = (void*)curr_data[1]) != NULL) { ... }

Answer 3

任务在C中是表述,因此你的工作就是如此。更改<代码>;至{>>>> 系指同一事项,而且更为清楚,至少是这样改动。如果你有更明确的选择(通常是真实的),那么在条件上的任务就应当避免,但如果这种选择是最为明确的,那么就应当加以利用。

转让的结果是被转让的物体:a = 价值将进行转让,然后评价为a。如<代码>a = b = 0。

为了进一步清理该法典,无需作废,如果是果园,则使用(无效),而不是使用NUL(只使用点人)。

Answer 4

您不必通过完全相当于“智商”的“智商”。

while (curr_data[1]) {
    curr_ptr = (void *)curr_data[1];