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How to MYSQL UPDATE fieldINT!=‘4’ doesn’t work [closed]
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Im trying to UPDATE queueStatusINT WHERE statusINT is 8 and queueStatusINT is NOT equal to 2 and type is $type. But I keep getting an error:

ERROR 1064 (42000) at line 1: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘ queueStatusINT!= 2’, type=’int   at line 1

Im using this SQL query to do the update:

UPDATE $mysqlTable SET queueStatusINT= 2’ WHERE statusINT= 8’, queueStatusINT!= 2’, type=‘$type’;

I have also noticed that I can do a NOT equal to in a SELECT command…

SELECT nameTXT FROM $mysqlTable WHERE queueStatusINT!= 2  ORDER BY queueStatusINT DESC, priorityINT DESC, id ASC LIMIT 7;
最佳回答

You need to use AND to combine your criteria, not just commas.

For example

UPDATE $mysqlTable 
SET    queueStatusINT =  2 
WHERE  statusINT      =   8 
AND    queueStatusINT !=  2 
AND    type           =   $type 
问题回答

Change your UPDATE to:

UPDATE $mysqlTable 
SET queueStatusINT= 2’ 
WHERE statusINT=8
AND queueStatusINT !=2 
AND type=‘$type’;

I assume queueStatusINT is an Integer (as the name suggests) - you should leave out the as they symbolize a string/character.

Best wishes, Fabian





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