因此，我正尝试将另一个列表的子集的反向附加到一个列表中。由于某些原因，解释器似乎不太喜欢它。这就是我正在做的。
list1.extend(list2[someInt:someOtherInt].reverse())
为什么这不是合法的？对我来说，这似乎是合理的。
除了Ignacio的答案，这里有一个解决方案。请尝试：
list1.extend(reversed(list2[someInt:someOtherInt]))
或者，您可以使用具有反向索引的切片，但要注意偏移量误差！
list1.extend(list2[someOtherInt - 1: someInt - 1: -1])
最好还是坚持使用第一种方法，因为第二种方法在0索引的情况下会失败。
与 reversed 相关，另一个技巧是，你可以使用 sorted(list1) 而不是 list1.sort()。
list方法在原地操作，意味着它们返回None。
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