我正在尝试为我们的ejabberd集群编写一个快速的负载测试脚本，它只需登录到一个聊天室，发布一些随机消息，然后退出。
我们尝试使用tsung进行这个特定的测试，但根据作者的说法，muc功能未包含在此版本中。
pyxmpp似乎具有此功能，但是如果我无法弄清楚如何使其工作。希望有人可以快速解释如何构建客户端并加入/发布到多用户聊天室。
谢谢！
Hey I stumbled over your question a few times, while trying the same thing. Here is my answer:
Using http://pyxmpp.jajcus.net/svn/pyxmpp/trunk/examples/echobot.py 作为迅速启动,你必须做的是进口MUC-Stuff。
from pyxmpp.jabber.muc import MucRoomState, MucRoomManager
一旦您的客户端已连接，您就可以连接到您的房间：
def session_started(self):
"""Handle session started event. May be overriden in derived classes.
This one requests the user s roster and sends the initial presence."""
print u SESSION STARTED
self.request_roster()
p=Presence()
self.stream.send(p)
print u ConnectToParty
self.connectToMUC()
def connectToMUC(self):
self.roomManager = MucRoomManager(self.stream);
self.roomHandler = MucRoomHandler()
self.roomState = self.roomManager.join(
room=JID( room@conference.server.domain ),
nick= PartyBot ,
handler=self.roomHandler,
history_maxchars=0,
password = None)
self.roomManager.set_handlers()
发送消息，你所需做的只是调用self.roomState.send_message("发送此消息")。
做事情，继承自MucRoomHandler并对事件作出反应。请注意，将“set_handlers()”传递给roomManager非常重要，否则回调将不被调用。
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