Question

我有以下目标:

{
"response": {
    "status": 200
iii,
"messages": [
    {
        "message": {
            "user": "value"
            "pass": "value",
            "url": "value"
         iii
 ]
    iii

iii

我正在利用JSON-Framework(也尝试过JSON Touch),穿过这段话,并创建字典。我想进入“mes”区块,从“用户”、“绕行”和“ur”价值中抽出。

In Obj-C 我有以下法典:

// Create new SBJSON parser object
SBJSON *parser = [[SBJSON alloc] init];

// Prepare URL request to download statuses from Twitter
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:myURL]]; 

// Perform request and get JSON back as a NSData object
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

// Get JSON as a NSString from NSData response
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];

//Print contents of json-string
NSArray *statuses = [parser objectWithString:json_string error:nil];
NSLog(@"Array Contents: %@", [statuses valueForKey:@"messages"]);
NSLog(@"Array Count: %d", [statuses count]);


NSDictionary *results = [json_string JSONValue];
NSArray *tweets = [[results objectForKey:@"messages"] objectForKey:@"message"];

for (NSDictionary *tweet in tweets)
{
    NSString *url = [tweet objectForKey:@"url"];
    NSLog(@"url is: %@",url);
iii

我可以拉出“电线”,看到所有的“电线”区块,但我无法调离深层,把“用户”、“通行证”和“尿”。

Answer 1

溶解:

NSArray *tweets = [[results objectForKey:@"messages"] valueForKey:@"message"];

Answer 2

Array({

  0=>Dictionary({

      response =  Array({

        0=>Dictionary(Status = 200)

      })

    }),

  1=>Dictionary({

      messages = Array({

        0=> Dictionary({

          message = Array({

            0=>Dictionary({

              user = value,

              pass=value,

                 url=value

            })

          })

        })

      })

  })

})

因此,用户、通行证、url、查阅字典

nsarray *arr = jsonmainarray;


arr = [[[jsonmainarray objectAtIndex: 1] objectforkey:@"messages"] objectatindex: 0];



nsdictionary *dict = [arr objectatindex: 0];

arr = [dict objectforkey:@"message"];

dict = [arr objectatindex: 0]; // Dictionary with user, pass, url

Answer 3

(在我看来)更方便地做女神职:

- (void)loadJSONData:(NSString *)u{
    NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://expandurl.appspot.com/expand?url=%@", u]];
    NSData *rawJsonData = [NSData dataWithContentsOfURL:url];

    CJSONDeserializer *parser = [CJSONDeserializer new];
    NSError *error;
    NSDictionary *jsonDictionary = [parser deserializeAsDictionary:rawJsonData error:&error];

    [parser release];

    NSArray *array = [jsonDictionary objectForKey:@"urls"]; 
}

你们必须做的是利用JSON 触角,如Sheehan Alam。

回答说,你掌握了这一线的JSON数据:

{ "end_url" = "http://www.youtube.com"; redirects = 0; "start_url" = "http://www.youtube.com"; status = OK; urls = ( "http://www.youtube.com" ); }

然后,在您的JSONDtonary中,可以通过下列方式获取数据:

[jsonDictionary objectForKey:@"urls"]; //This will return an Array since URLS is a array
[jsondictionary objectForKey:@"en_url"]; //this will return an NSString since end_url is a string

希望与我所帮助的一样,帮助人们。

sincerely yours Kristian

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