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原标题:Threads are not processing any requests(Help Required In Multithreading application)

I am working in multithreading application, application is facing some problem while processing the request. When i kept load on multithreaded application,it is working fine up to some time.After some time it is not able to process any request.At this situation when type this command,

页: 1

所有这一切都表明了这一点,我想理解“13:45?”这个问题是什么标志? 实际含义如何?

root 15818 8838 15833 0 1036 2731192 137308 4 13:45 ? 00:00:02 multithread
root 15818 8838 15834 0 1036 2731192 137308 4 13:45 ? 00:00:02 multithread
root 15818 8838 15835 0 1036 2731192 137308 4 13:45 ? 00:00:01 multithread
root 15818 8838 15836 0 1036 2731192 137308 4 13:45 ? 00:00:00 multithread
root 15818 8838 15837 0 1036 2731192 137308 1 13:45 ? 00:00:11 multithread
root 15818 8838 15838 0 1036 2731192 137308 2 13:45 ? 00:00:00 multithread
root 15818 8838 15839 0 1036 2731192 137308 3 13:45 ? 00:00:00 multithread
root 15818 8838 15840 0 1036 2731192 137308 2 13:45 ? 00:00:10 multithread
root 15818 8838 15841 0 1036 2731192 137308 2 13:45 ? 00:00:12 multithread
root 15818 8838 15842 0 1036 2731192 137308 3 13:45 ? 00:00:06 multithread
root 15818 8838 15843 0 1036 2731192 137308 2 13:45 ? 00:00:01 multithread
root 15818 8838 15844 0 1036 2731192 137308 4 13:45 ? 00:00:02 multithread
root 15818 8838 15845 0 1036 2731192 137308 5 13:45 ? 00:00:13 multithread
root 15818 8838 15846 0 1036 2731192 137308 4 13:45 ? 00:00:01 multithread
root 15818 8838 15847 0 1036 2731192 137308 4 13:45 ? 00:00:00 multithread
root 15818 8838 15848 0 1036 2731192 137308 4 13:45 ? 00:00:01 multithread
root 15818 8838 15849 0 1036 2731192 137308 4 13:45 ? 00:00:07 multithread
root 15818 8838 15850 0 1036 2731192 137308 2 13:45 ? 00:00:00 multithread
root 15818 8838 15851 0 1036 2731192 137308 4 13:45 ? 00:00:03 multithread
root 15818 8838 15852 0 1036 2731192 137308 2 13:45 ? 00:00:06 multithread

问题回答

“?” 只是意味着这些进程没有“控制TTY”,这只是意味着它们基本上重新起步。

由于你对贵方案的内容、它所写的文字或理应做些什么,我们很难提供更多的援助。

采用(g)的分解符号,然后使用gdb作为加工的附加物,例如:

gdb multithread
att 15818

因此,你可以使用“完全适用”来获得每条透镜的后退。 这应当告诉你他们正在等待什么。





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