Question

需要一个运行(移动、滚动)平均算法来计算5分钟的平均轨道。我必须全力以赴,对通过的轨道具有累积价值。

例如: 首先,5分钟后,我有10个轨道,因此,我的平均数是10个轨道。 5分钟后,我有15个轨道,因此,现在我的平均数是7.5个轨道。另有5分钟后,我有30个轨道,因此,现在的平均数是10.8个轨道。

我的问题是,我如何在C++中执行一个时段,这样就会在大约5分钟的间隔中测出比值? 显然,我可以动用300秒的拖延。但是,我能否在每5分钟仅发射一次事件(借方价值)的情况下拿出时间?

Answer 1

www.un.org/Depts/DGACM/index_spanish.htm 我先前的答复:。

#define REENTRANT
//The above is neccessary when using threads. This must be defined before any includes are made
//Often times, gcc -DREENTRANT is used instead of this, however, it produces the same effect

#include <pthread.h>

char running=1;

void* timer(void* dump){
    unsigned char i=0;
    while(running){
        for(i=0;i<300 && running;i++){
            sleep(1);//so we don t need to wait the 300 seconds when we want to quit
        }
        if(running)
           callback();//note that this is called from a different thread from main()
    }
    pthread_exit(NULL);
}

    int main(){
    pthread_t thread;
    pthread_create(&thread,NULL,timer,NULL);
    //do some stuff
    running=0;
    pthread_join(thread,NULL);//we told it to stop running, however, we might need to wait literally a second
    pthread_exit(NULL);
    return 0;
}

Answer 2

“umb”解决办法是使用苯胺read。你们可以做一个read子,然后把它放在睡觉中。

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