Question

我用下面的文字执行一个过程,把其产出隐藏在沙尔。它只是一个 lo,在分进程结束之前,我需要一种阻挡的办法,然后才转向下一个迭代。

subprocess.Popen(["scanx", "--udp", host], stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

Answer 1

使用>subprocess.quest()。参考:

subprocess.call(*popenargs, **kwargs)
Run command with arguments. Wait for command to complete, then return the returncode attribute. The arguments are the same as for the Popen constructor.

<><>Edit>:

wait(,和wait(>>>>>> >) 易陷入僵局(如Tomy Herbert指出)。参考:

Warning: This will deadlock if the child process generates enough output to a stdout or stderr pipe such that it blocks waiting for the OS pipe buffer to accept more data. Use communicate() to avoid that.

因此,如果你的指挥产生大量产出,则使用communicate(。相反:

p = subprocess.Popen(
    ["scanx", "--udp", host],
    stdin=subprocess.PIPE,
    stdout=subprocess.PIPE,
    stderr=subprocess.PIPE)
out, err = p.communicate()

Answer 2

如果你不需要产出,那么你可以把牛奶通过<条码>tdout和<条码>stderr。我不知道这是否能够发挥作用,但会带来一种uf。现在使用<代码>分处理。不要再陷入僵局

import os
import subprocess

null = open(os.devnull,  w )
subprocess.call([ ls ,  -lR ], bufsize=4096, stdout=null, stderr=null)

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