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按全球变量分列的数据框架
原标题:R data frame select by global variable

我不敢确定如何做到这一点,而不会产生错误。 这是我问题的简化例子。

Say我有这个数据框架。

a   b  c  d
1   2  3  4
2   3  4  5
3   4  5  6

然后我有变数。

x <- min(c(1,2,3))

我现在想做以下工作:

y <- DF[a == x]

但是,当我试图提及像“x”这样的一些变数时,我发现了一个错误,因为R在我的数据框架内正在研究一个“x”栏。 我拿到“选定的未界定栏目”错误

我如何在R?

最佳回答

我认为,这是你回顾的:

> x <- min(DF$a)
> DF[DF$a == x,]
  a b c d
1 1 2 3 4

更为容易的方式(避免x变量)是:

> DF[which.min(DF$a),]
  a b c d
1 1 2 3 4

> subset(DF, a==min(a))
  a b c d
1 1 2 3 4
问题回答

阅读Introduction to R,特别是矩阵、数据、框架和索引。 页: 1 你的比较没有工作。

或许你指的是

R> DF$a == min(c(1,2,3))
[1]  TRUE FALSE FALSE
R> DF[,"a"] == min(c(1,2,3))
[1]  TRUE FALSE FALSE
R> 

这告诉你,第一行也行不通。 在<代码>上打字,(>)就给你索引。





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