Question

我有一套图像途径,收集更多的图像物体(Which有一条道路财产)。我有密码检查任何对等图像,但如果应该有四条相匹配的图像途径(因为第一次收集的数字是多少),那么我如何在没有书面文件的情况下找到失踪人员?

        List<string> ImagesToCheck = new List<string>()
        {
            "",
            "s",
            "ssdd"
        };

        IEnumerable<HtmlImage> Images = manager.ActiveBrowser.Find.AllControls<HtmlImage>();

        var v = from i in Images
                where ImagesToCheck.Any(x => x == i.Src)
                select i;

        if (v.Count() < 3)
        {

        }

因此,我需要把“not

我怎么能够用准则Q这样做?

增编

Answer 1

引证。

var images = from s in ImagesToCheck where !i.Any(c => c.Path == s) select s;

大致如此。

Ian

Answer 2

图像图。 (x =>!v.Contains(x))

Answer 3

var images = from s in ImagesToCheck where i.All(c => c.Path != s) select s;

Answer 4

It s been a while since this answer was posted, but Linq has Intersect and Except. The last one will give you all the items from the first collection, except those that are also in the second collection. Disadvantage is that Except uses the standard Equals() operator or an IEqualityComparer<T> and you are matching on the Path property. But eventually you will be able to write something like:

ImagesToCheck.Except(Images)

我认为,什么是 ne。

Answer 5

var results = ImagesToCheck.Where(i => !v.Contains(i));

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