我写了一张包裹,希望用一种等效法来界定在大量来源档案中应当有效的某些类型。 这些“类型”仅与[u]int16/32/64_t不同,但有助于区分功能参数。
可以使用<代码>使用MyId=System。 Int32;,但这需要在每一档案中重新公布,直至我看到......。 是否有更好的办法?
一种替代做法是使用一种具有含蓄地转换为基本类型的内容。
public struct MyHandle
{
private int _handle;
internal MyHandle(int handle)
{
_handle = handle;
}
public static implicit operator int(MyHandle handle)
{
return handle._handle;
}
}
你的内部法典仍然可以通过默示转换将其用作基本类型(在此情况下),但你将它作为强类暴露于使用者。 你们的使用者也可以看到暗中的价值,尽管这种价值对他们来说是毫无意义的。 他们可以直接 cast你。 手提型,因为建筑商是内部的,你没有为另一方向提供转换操作员。
自2006年以来 我假定你想要区分合法使用“IDnt32”和你的习俗,是你们需要用人工指你们希望使用的一切东西。
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