我怎样才能将民族解放军的价值观列入Oracle/PLSQL?
我只想计算出无效价值。 是否有这样的职能?
我怎样才能将民族解放军的价值观列入Oracle/PLSQL?
我只想计算出无效价值。 是否有这样的职能?
我不知道Oracle specifally,但ANSI,COUNT(rowName)
,不计算
NUL
Value,而是COUNT(*)
。 因此,你可以写
SELECT COUNT(*) FROM YourTable WHERE YourColumn IS NULL
你们的兄弟们把你们的兄弟们带到民族解放军。
As an alternative to mdma s response. If you don t want to put a filter in the where you can
SELECT COUNT(case when xxx IS NULL THEN 1 end) cnt_xxx_null
FROM table
Oracle 指出:
All aggregate functions except COUNT(*) and GROUPING ignore nulls. You can use the NVL function in the argument to an aggregate function to substitute a value for a null.
举例来说,采用家庭结构:
SQL> select empno, sal, comm
2 from emp;
EMPNO SAL COMM
---------- ---------- ----------
7369 800
7499 1600 300
7521 1250 500
7566 2975
7654 1250 1400
7698 2850
7782 2450
7788 3000
7839 5000
7844 1500 0
7876 1100
7900 950
7902 3000
7934 1300
14 rows selected.
可以看出,商业一栏有4项已知的数值(即不作废)和10项不知名的数值(即Null)。
作为<编码>(your_column_name) 忽视你需要把不为人知的价值观替代你们可以提到的东西。 可通过NVL功能来实现。
SQL> select count(nvl(comm, -1)) "number of null values"
2 from emp
3 where nvl(comm, -1) = -1;
number of null values
---------------------
10
我将“-1”的价值作为“别名”用于我的无效价值,因为我知道,“-1”不是一栏中的现有价值。
http://www.un.org。
根据强有力的建议。 可从上述例子中删除该条款,并使用NVL2功能如下:
SQL> select count(nvl2(comm,null,-1)) "number of null values"
2 from emp
3 /
number of null values
---------------------
10
如果你想把其他价值计算到null。 然后使用COALESCE功能将改进执行时间。
SELECT COUNT(COALESCE( _COLUMN, 1)) AS CNT FROM _TABLE
我可能会试图推翻无效,见结果。
SELECT
COUNT(DECODE(YourField, null, 1, null)) Nulls,
count(*) Everything,
COUNT(YourField) NotNulls
FROM YourTable
一切均应平等
select count(nvl(values, 0)) from emp where values is null;
职能:
create or replace function xxhrs_fb_count_null
return number
as
l_count_null number;
begin
select count(*) into l_count_null from emp where comm is null;
return l_count_null;
end;
使用:
select xxhrs_fb_count_null from dual
I believe your requirement is as below:
Table emp
has 100 rows. Against 20 employees, HIRE_DATE
column is NULL
. So basically, you want to get 20 as output.
This is another method apart from the answers given by other contributors in this forum.
-- COUNT (1) would return 100
-- COUNT (hire_date) would return 80
-- 100 - 80 = 20
SELECT COUNT (1) -
COUNT (hire_date)
AS null_count
FROM emp;
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