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如何在C#中调用数学表述? [复制]
原标题:How to parse math expressions in C#? [duplicate]
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Closed 13 years ago.

Possible Duplicate:
Is there a string math evaluator in .NET?

Can C# parse mathematical expressions such as y=3*x + 3 into string? If so, ho? I appreciate your help.

问题回答

Here s a bit of code I wrote a while ago to parse infix (operator operand operator) equations. There are some small classes and helper functions missing, but it should be fairly easy to implement them. If you need them or any help with it, let me know and I can upload them somewhere.

它基本实施Dijkstra s Shunting-院算

public Operand ExpressionTree
{
    get;
    private set;
}

private Stack<Operands.Operand> stack = new Stack<InfixParser.Operands.Operand>();
private Queue<Operands.Operand> outputQueue = new Queue<InfixParser.Operands.Operand>();

private void ParseFormulaString()
{
    //Dijkstra s Shunting Yard Algorithm
    Regex re = new Regex(@"([+-*()^/ ])");
    List<String> tokenList = re.Split(formulaString).Select(t => t.Trim()).Where(t => t != "").ToList();

    for (int tokenNumber = 0; tokenNumber < tokenList.Count(); ++tokenNumber)
    {
        String token = tokenList[tokenNumber];
        TokenClass tokenClass = GetTokenClass(token);

        switch (tokenClass)
        {
            case TokenClass.Value:
                outputQueue.Enqueue(new Value(token));
                break;
            case TokenClass.Function:
                stack.Push(new Function(token, 1));
                break;
            case TokenClass.Operator:
                if (token == "-" && (stack.Count == 0 || tokenList[tokenNumber - 1] == "("))
                {
                    //Push unary operator  Negative  to stack
                    stack.Push(new Negative());
                    break;
                }
                if (stack.Count > 0)
                {
                    String stackTopToken = stack.Peek().Token;
                    if (GetTokenClass(stackTopToken) == TokenClass.Operator)
                    {
                        Associativity tokenAssociativity = GetOperatorAssociativity(token);
                        int tokenPrecedence = GetOperatorPrecedence(token);
                        int stackTopPrecedence = GetOperatorPrecedence(stackTopToken);

                        if (tokenAssociativity == Associativity.Left && tokenPrecedence <= stackTopPrecedence ||
                            tokenAssociativity == Associativity.Right && tokenPrecedence < stackTopPrecedence)
                        {
                            outputQueue.Enqueue(stack.Pop());
                        }
                    }
                }
                stack.Push(new BinaryOperator(token, Operator.OperatorNotation.Infix));
                break;
            case TokenClass.LeftParen:
                stack.Push(new LeftParenthesis());
                break;
            case TokenClass.RightParen:
                while (!(stack.Peek() is LeftParenthesis))
                {
                    outputQueue.Enqueue(stack.Pop());
                }
                stack.Pop();

                if (stack.Count > 0 && stack.Peek() is Function)
                {
                    outputQueue.Enqueue(stack.Pop());
                }
                break;
        }

        if (tokenClass == TokenClass.Value || tokenClass == TokenClass.RightParen)
        {
            if (tokenNumber < tokenList.Count() - 1)
            {
                String nextToken = tokenList[tokenNumber + 1];
                TokenClass nextTokenClass = GetTokenClass(nextToken);
                if (nextTokenClass != TokenClass.Operator && nextTokenClass != TokenClass.RightParen)
                {
                    tokenList.Insert(tokenNumber + 1, "*");
                }
            }
        }
    }

    while (stack.Count > 0)
    {
        Operand operand = stack.Pop();
        if (operand is LeftParenthesis || operand is RightParenthesis)
        {
            throw new ArgumentException("Mismatched parentheses");
        }

        outputQueue.Enqueue(operand);
    }

    String foo = String.Join(",", outputQueue.Select(t => t.Token).ToArray());
    String bar = String.Join("", tokenList.ToArray());

    Stack<Operand> expressionStack = new Stack<Operand>();
    while (outputQueue.Count > 0)
    {
        Operand operand = outputQueue.Dequeue();

        if (operand is Value)
        {
            expressionStack.Push(operand);
        }
        else
        {
            if (operand is BinaryOperator)
            {
                BinaryOperator op = (BinaryOperator)operand;
                Operand rightOperand = expressionStack.Pop();
                Operand leftOperand = expressionStack.Pop();
                op.LeftOperand = leftOperand;
                op.RightOperand = rightOperand;
            }
            else if (operand is UnaryOperator)
            {
                ((UnaryOperator)operand).Operand = expressionStack.Pop();
            }
            else if (operand is Function)
            {
                Function function = (Function)operand;
                for (int argNum = 0; argNum < function.NumArguments; ++argNum)
                {
                    function.Arguments.Add(expressionStack.Pop());
                }
            }

            expressionStack.Push(operand);
        }
    }

    if (expressionStack.Count != 1)
    {
        throw new ArgumentException("Invalid formula");
    }

    ExpressionTree = expressionStack.Pop();
}

private TokenClass GetTokenClass(String token)
{
    double tempValue;
    if (double.TryParse(token, out tempValue) ||
        token.Equals("R", StringComparison.CurrentCultureIgnoreCase) ||
        token.Equals("S", StringComparison.CurrentCultureIgnoreCase))
    {
        return TokenClass.Value;
    }
    else if (token.Equals("sqrt", StringComparison.CurrentCultureIgnoreCase))
    {
        return TokenClass.Function;
    }
    else if (token == "(")
    {
        return TokenClass.LeftParen;
    }
    else if (token == ")")
    {
        return TokenClass.RightParen;
    }
    else if (binaryInfixOperators.Contains(token))
    {
        return TokenClass.Operator;
    }
    else
    {
        throw new ArgumentException("Invalid token");
    }
}

private Associativity GetOperatorAssociativity(String token)
{
    if (token == "^")
        return Associativity.Right;
    else
        return Associativity.Left;
}

private int GetOperatorPrecedence(String token)
{
    if (token == "+" || token == "-")
    {
        return 1;
    }
    else if (token == "*" || token == "/")
    {
        return 2;
    }
    else if (token == "^")
    {
        return 3;
    }
    else
    {
        throw new ArgumentException("Invalid token");
    }
}

明显重复:

是否有数字评价器,载于

答案是没有的,因为长期答案是联系。 (我建议采用铜.解决方案。) iii

Why don t you use Simple Math Parser or something is same? link text

在最近一项银星应用中,我采取了廉价办法,用reg(安全)的reg光,将其传给 Java本评价员。 它实际上运作良好,但我承认它是一个黑客。

http://josheinstein.com/blog/index.php/2010/03/mathevalconverter





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