I m 执行一个以身为单位的低价竞标,I ve试图在解释或概述处理主食的算法的文献上阅读。 例如:
int i = 3
int j = 4
int k = 5
让我们选择<代码>i,j,和k为当地变量,因此这些变量传统上将储存在 st上。 编组/条码翻译将研究如下内容:
pushi 3
pushi 4
pushi 5
标题是:<代码>5 4 3。
我有笔记和笔记,因此有<代码>pushi/code>。 然而,我的问题是,在座标上(有的<编码>ptr*或字面识别),编辑或口译将如何知道,如果我想做像int x = i j,在定义之后,我必须填写2<>/strong>和,分别为
我希望我的问题具有某种意义,而且也许会采取更加划时代的办法: 感谢你们的见解!
通常用一个叫做tackframe。 您一度为all本地变量(分配/开发成登记册的变数)分配空间,储存该块的基址,并在该区被抵消后运作。 接着,在范围撤出的 st脚石中, everything掉一切。
汇编者这样做的是,通过直接添加ack点,然后在不使用推力和用正常记忆读功能的情况下,将 index升为平价。 之后,在完成后将 st回原价值。
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