Question

我愿学习最佳方法,在PySimpleGUI和PySimpleGUI及PyS框架中形成一个人口窗口,即一个无锁的人群(隔read的read),如果用户把Cancel但ton点击到pop窗上,或者通过将“cl”指挥到pop的主方案,就可以关闭。非常感谢。 - Joe

我先使用PySimpleGUI的 s(PySimpleGUI)功能,并熟悉利用参数进行基本定制。

Answer 1

有必要通过 yourself来创造人口窗口,因此,你可以添加密码,说明你如何用纽子点击来关闭一个人口窗口。

from random import randint
import PySimpleGUI as sg

def new_window(index):
    w, h = sg.Window.get_screen_size()
    location = (randint(500, w-500), randint(200, h-200))
    layout = [[sg.Text(f This is sub-window {index} , key= TEXT )], [sg.Button( OK )]]
    return sg.Window(f Window {index} , layout, location=location, no_titlebar=True, finalize=True)

layout = [[sg.Button( New Window )]]
main_window = sg.Window( Main Window , layout=layout, finalize=True)
windows = [main_window]
index = 0
while True:

    win, event, values = sg.read_all_windows()

    if event in (sg.WINDOW_CLOSED,  OK ):
        if win == main_window:
            break
        win.close()
        windows.remove(win)
        index -= 1
        for i, w in enumerate(windows[1:]):
            w[ TEXT ].update(f This is sub-window {i+1} )

    elif event ==  New Window :
        index += 1
        new_win = new_window(index)
        windows.append(new_win)
        main_window.force_focus()

for win in windows:
    win.close()

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