Question

工作罚款:

import urllib2

opener = urllib2.build_opener(
                urllib2.HTTPHandler(),
                urllib2.HTTPSHandler(),
                urllib2.ProxyHandler({ http :  http://user:pass@proxy:3128 }))
urllib2.install_opener(opener)
print urllib2.urlopen( http://www.google.com ).read()

但是,如果是<> 改为:

...
print urllib2.urlopen( https://www.google.com ).read()

存在错误:

Traceback (most recent call last):
  File "D:Temp6	mp.py", line 13, in <module>
    print urllib2.urlopen( https://www.google.com ).read()
  File "C:Python26liburllib2.py", line 124, in urlopen
    return _opener.open(url, data, timeout)
  File "C:Python26liburllib2.py", line 389, in open
    response = self._open(req, data)
  File "C:Python26liburllib2.py", line 407, in _open
     _open , req)
  File "C:Python26liburllib2.py", line 367, in _call_chain
    result = func(*args)
  File "C:Python26liburllib2.py", line 1154, in https_open
    return self.do_open(httplib.HTTPSConnection, req)
  File "C:Python26liburllib2.py", line 1121, in do_open
    raise URLError(err)
URLError: <urlopen error [Errno 10060]

为什么以及如何解决这一问题?

Answer 1

改变这一思路:

urllib2.ProxyHandler({ http :  http://user:pass@proxy:3128 }))

为此:

urllib2.ProxyHandler({ https :  http://user:pass@proxy:3128 }))

它对我课以罚款。

Answer 2

在Windows, errno 10060是一个胜诉的错误,意思是连接时间已久。您能否到https://www.google.com 。 http://user:pass@proxy:3128 “rel=” ? 您能否确保您的代理服务器能够在同一港口操作https和https?

Answer 3

documentation lli2说:

Note: Currently urllib2 does not support fetching of https locations through a proxy. However, this can be enabled by extending urllib2 as shown in this recipe.

我必须承认,就Jython 2.5.3而言,我 work不工作,但我仍在尝试。

,p至Jython 2.5.3,为我工作。我现在可以把HTTPS的资源压在代理服务器上。

www.un.org/Depts/DGACM/index_spanish.htm 这里的守则是,向HTTPS资源提供吉大港山区基本认证(DON T FORGET TO INSTALL PATCHIRST(见前次更新)):

from suds.client import Client
from suds.transport.https import HttpAuthenticated

credentials = dict(username= ... , password= ... , proxy={ https :  host:port ,  http :  host:port })
t = HttpAuthenticated(**credentials)
url =  https://example.com/service?wsdl 
client = Client(url, transport=t)
print client.service.getFoo()

友情链接