我从被控制到没有管理的总结正在处理许多数据,这一功能是:人类健康基金会将要求每个数据都使用新的数据,这对我来说是一个大的打击。 因此,我的问题是:
Can 我分配了一个未管理的记忆库,并用它来将管理的数据类型转换成手无管理的类别?
我从被控制到没有管理的总结正在处理许多数据,这一功能是:人类健康基金会将要求每个数据都使用新的数据,这对我来说是一个大的打击。 因此,我的问题是:
Can 我分配了一个未管理的记忆库,并用它来将管理的数据类型转换成手无管理的类别?
假设<代码>的所有特性 系统:标准代码>在ASCII范围内,最基本的实施方式如下:
void ConvertAndCopy(System::String^ ms, char* us)
{
for (int i(0); i < ms->Length; ++i)
us[i] = static_cast<char>(ms[i]);
us[ms->Length] = ;
}
// usage example:
System::String^ ms = "Hello world";
char us[12] = "";
ConvertAndCopy(ms, us);
请注意,这并不对目的地阵列进行约束检查,也不造成任何性质的转换。
这是否优于<代码>。 努力争取全球安提斯/代码,或者任何业绩收益是否值得复杂程度的大幅提高(即管理你自己的记忆和处理特征的转换),我对此没有想法。
引来这颗子弹。
char *poutputString = (char *)(void *)Marshal::StringToHGlobalAnsi(inputString);
// do something with poutputString here
Marshal::FreeHGlobal(poutputString);
这是我所看到的唯一方法。 您能提供在你的案件中如何使用的密码?
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