Question

我试图开一个档案,我刚刚认识到,我与我的用户名(俄罗斯语)有麻烦。关于如何适当校正/编码从而实现闲 to的建议?

I m, p. 2.6.5

xmlfile = open(u"D:\Users\Эрик\Downloads\temp.xml", "r")

Traceback (most recent call last):
  File "<pyshell#23>", line 1, in <module>
    xmlfile = open(str(u"D:\Users\Эрик\Downloads\temp.xml"), "r")
UnicodeEncodeError:  ascii  codec can t encode characters in position 9-12: ordinal not in range(128)

os.sys.getfilesystemencoding() mbcs

xmlfile = open(u”D:UsersЭ Zuloudownloads emp.xml.encode(“mbcs”),“r”

Traceback (most recent call last): File "", line 1, in xmlfile = open(u”D:UsersЭ Zuloudownloads emp.xml.encode(“mbcs”),“r” IOError: [Errno 22] invalid mode ( r ) or filename: D:UsersY?eeDownloads emp.xml

Answer 1

第一个问题是,除非你使用<代码>r”raw quote"。在2.6.5中,你需要专门处理你统法协会的编码,但你可能需要在你的源代码中提出文件编码,如:

# -*- coding: utf-8 -*-

http://www.python.org/dev/peps/pep-0263/“rel=“nofollow noreferer”>。它是互动协作的一个例子:

$ python
Python 2.6.5 (r265:79063, Apr 16 2010, 13:09:56) [GCC 4.4.3] on linux2
>>> f = r"D:UsersЭрикDownloads	emp.xml"
>>> f
 D:\Users\xd0xadxd1x80xd0xb8xd0xba\Downloads\temp.xml 
>>> x = open(f,  w )
>>> x.close()
>>> 
$ ls D*
D:UsersЭрикDownloads	emp.xml

是的,这属于一个特殊系统,因此,<条码>><>>> 代码> 具有实际意义,我的终端编码为utf-8,但运作良好。在阅读档案时,你可能只得向牧师提供 co。

Answer 2

www.un.org/Depts/DGACM/index_spanish.htm 第一期:

xmlfile = open(u"D:\Users\Эрик\Downloads\temp.xml", "r")
### The above line should be OK, provided that you have the correct coding line
### For example # coding: cp1251

Traceback (most recent call last):
  File "<pyshell#23>", line 1, in <module>
    xmlfile = open(str(u"D:\Users\Эрик\Downloads\temp.xml"), "r")
### HOWEVER the above traceback line shows you actually using str()
### which is DIRECTLY causing the error because it is attempting
### to decode your filename using the default ASCII codec -- DON T DO THAT.
### Please copy/paste; don t type from memory.
UnicodeEncodeError:  ascii  codec can t encode characters in position 9-12: ordinal not in range(128)

<>第二个问题:

<>代码>.sys.getfilesystemencoding(/code>

xmlfile = open(u"D:UsersЭрикDownloads	emp.xml".encode("mbcs"), "r")
### (a) 	 is interpreted as a TAB character, hence the file name is invalid.
### (b) encoding with mbcs seems not to be useful; it messes up your name ("Y?ee").

Traceback (most recent call last):
File "", line 1, in xmlfile = open(u"D:UsersЭрикDownloads	emp.xml".encode("mbcs"), "r")
IOError: [Errno 22] invalid mode ( r ) or filename:  D:UsersY?eeDownloads	emp.xml

www.un.org/Depts/DGACM/index_spanish.htm 关于Windows硬编码名称的一般建议,按优先排序:

(1) Don t
(2) Use / e.g. "c:/temp.xml"
(3) Use raw strings with backslashes r"c: emp.xml"
(4) Use doubled backslashes "c:\temp.xml"

友情链接