然而,一个基本问题,但一个似乎压倒我的问题。
考虑到“通用”:
IEnumerable<KeyValuePair<TKey, TValue>>
难道这说明,可以计算出的电子电子电子数据能够有通用的类型,而这种类型本身是关键数字。
感谢
Scott
是的。 关键类别预计有两种通用参数。 我们可以指出具体类型:
IEnumerable<KeyValuePair<string, int>>
或者,我们可以通过使用外部类别已经规定的其他通用参数来充实:
class Dictionary<TKey, TValue> : IEnumerable<KeyValuePair<TKey, TValue>>
通用类型参数总是被指明为“用途”,或者在你使用需要这些参数的类别或方法时。 就像任何其他参数一样,你可以以固定的硬编码价值(或此处的类型)或另一种变数来填充。
是的,这是“一千五千五千五百五千五千五百五千五千五千五千五百五千五千五千五千五千五千五百千五千五百千五千五千五千五百千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五百五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五百五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五千五百 因此宣布:
IEnumberable<KeyValuePair<string, string>> reallyComplicatedDictionary =
new IEnumerable<KeyValuePair<string, string>>();
类似情况。
关于唯一的想法,我可以认为,这种特殊做法是允许你拥有一个重复钥匙的“独裁者”。
简言之,意思是,当你在<条码>上列举时。 页: 1 KeyValuePair<TKey,TValue>(针对任何种类的TKey和>
因此,是。
这里
IEnumerable<KeyValuePair<string, int>>
The IEnumerable itself is not a generic. It knows that it is going to contain KeyValuePair. 这里KeyValuePair is the generic which can contain any 2 generic types.
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