我正试图找一个雷克斯替代机构,努力更新我的议会信息文件。
Regex.Replace(
contents,
@"([assembly: Assembly(File)?Version("").*("")])",
"$1" + version + "$3"
);
问题在于,<代码>,<> 是1.5.3.0>,因此,在评价替换时,见,11.5.3.0美元“,并大概看第十一个被捕获群体,因为它是:
$11.5.3.0")]
如果在<代码>1美元后保留一个空间,则该空间可进行罚款。 在不实际插入字面的情况下,我需要怎么做才能逃脱第二位数?
使用<代码>${1}而不是$1。 http://msdn.microsoft.com/en-us/library/bs2twtah.aspx” rel=“noretinger” 捕获组<<>代码>(?<name>)。
The s snippet to show (,另见关于ideone.com:
Console.WriteLine(Regex.Replace("abc", "(.)", "$11")); // $11$11$11
Console.WriteLine(Regex.Replace("abc", "(.)", "${1}1")); // a1b1c1
Console.WriteLine(Regex.Replace("abc", "(?<x>.)", "${x}1")); // a1b1c1
这种行为明确记录在案:
Regular Expression Language Elements - Substitutions
Substituting a Numbered Group
<代码> 序号 语文部分包括最后一项与<代码>/代码>对应的编号。 替换舱位中的捕获组,
编号是捕获组的索引。如果<代码>>>>>没有具体规定固定表述方式界定的有效捕获组,
$被解释为literal nature series,用以取代每一配方。Substituting a Named Group
<代码> 姓名><>/代码> 语文要素替换了与<代码> 姓名>/代码>格格言对应的最后一个次体,其中<代码> 姓名/代码>是指由<代码>界定的代号组的名称(>?< 姓名和gt; 语文要素。
如果<代码> 姓名/代码>没有具体说明固定表述方式界定的有效名称捕获组,
${name><>/code>被解释为literal nature series,用以取代每一配方。
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