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• 如何产生8个特惠值? [闭门]
原标题:How to generate 8 byte hex value? [closed]

我想在C中生成这一顺序数据:

data_packet[1] = 0706050403020100 (seed_value)

下次

data_packet[2] = 0f0e0d0c0b0a0908

Next will be the 下次 8 hexadecimal characters and so on for say 100 bytes. How can I do it? Can we do it using character array?

最佳回答

您不希望使用<条码>代谢/编码>阵列,因为<条码>可签署或不得签署(定义实施)。 如果您的六分位数从0x00到0xFF,我强烈建议使用<代码>unsign char/code>阵列。

阵列中的价值观一样,从0到N是依次的。 这表示使用<>条码>。

这个阵列的固定尺寸为8个 by。 Hmmm, a for loop.

你们的任务几乎部分是tes客的方向。 例如,从第7位起或从第0位起填补阵列?

因此,这里有一些皮索多法帮助你:

For each value from 0 to N do:
begin
  for array position from 0 to 7 do: // or from 7 to 0
    put  value  into the array at  position ;
  call function to process the array.
end

更不用说,将“产出价值”的功能改为“随机值”。

如果你想要我们实际上写你的节目,让我们知道。 我可以动用额外资金。

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