在使用“<代码>><>>>/代码”的操作人员时,加上背心,为什么我需要使用“zy匹配”? 似乎如<代码>而不是。 应当打破这种对比。
例如:
<?php
preg_match( /(t)[^1]*1/ , is this test ok , $matches);
echo $matches[0];
?>
<http://codepad.viper-7.com/BPDeLx” rel=“nofollow noreferer”>>>>this testt t,尽管中文本<>t 与[^1]不一致。 我们需要使用>/(t)[^1]*?<1/code>,以便与<编码>相匹配。
而且
preg_match( /t[^t]*t/ , is this test ok , $matches);
正在发生什么,我有什么误解?
之所以没有工作,是因为此处的<代码>1不是特性类别中的背书。 <代码>1被解释为具有ASCII值的特性。
你可以采取消极态度,而是要取得你想要的效果:
/(t)(?:(?!1).)*1/
您不能在品行内使用背书。 <代码>[^1]系指“除<代码>1以外的任何特性”。
相反,使用<条码>/(t)(?:!?”
<代码>(?:......)
(?!) is a “negative look-ahead”, claiming that the subexpression doesn t对等
<代码>1为单一特性时,指“与<代码>1不一致的任何特性”。
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