Question

我有两张表格,页数和员额,都列在自动取款机上,并使用页数加入表。

我的页面模型与HABTM的定义包含一个功能。

class Page extends AppModel
{
   var $name = "Page";
   ......
   ......
   function callthis()
   {
     return $this->find( all );;
   }
}

我从我的员额控制员那里试图称职。

class PostsController extends AppController
{
    ....
    ....
    function index()
    {
      $returned = $this->Post->Page->callthis();
    }
}

结果是

Warning (512): SQL Error: 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near  threadedpages  at line 1 [CORE/cake/libs/model/datasources/dbo_source.php, line 681]

进一步预测产出:

法典

        $out = null;
        if ($error) {
            trigger_error( <span style="color:Red;text-align:left"><b>  . __( SQL Error: , true) . "</b> {$this->error}</span>", E_USER_WARNING);

背景

$sql    =   "threadedpages"
$error  =   "1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near  threadedpages  at line 1"
$out    =   null

呼吁

DboSource::showQuery() - CORE/cake/libs/model/datasources/dbo_source.php, line 681
DboSource::execute() - CORE/cake/libs/model/datasources/dbo_source.php, line 266
DboSource::fetchAll() - CORE/cake/libs/model/datasources/dbo_source.php, line 410
DboSource::query() - CORE/cake/libs/model/datasources/dbo_source.php, line 364
Model::call__() - CORE/cake/libs/model/model.php, line 502
Overloadable::__call() - CORE/cake/libs/overloadable_php5.php, line 50
AppModel::threadedpages() - [internal], line ??
PostsController::admin_index() - CORE/plugins/cakey/controllers/posts_controller.php, line 11
Dispatcher::_invoke() - CORE/cake/dispatcher.php, line 204
Dispatcher::dispatch() - CORE/cake/dispatcher.php, line 171
[main] - APP/webroot/index.php, line 83

应在《基本生活标准》中规定相关的示范功能? 如果我们检查

$this->Recipe->Tag->find( all , array( conditions =>array( Tag.name => Dessert )));

当找到塔格模型的功能时,可以从相关的收款控制员那里召来,为什么我会从相关的员额控制员那里打电话给页模型。

Answer 1

正如斯蒂芬和莫雷诺指出的,我的关系确实存在问题。

http://book.cakephp。如果我们需要在你的gin子里提及一种模式,我们需要把假名与模版名称分开。

我在不使用Plugin的情况下直接提到了这些模型。模式为Name。谢谢大家。

Answer 2

这个问题在你的关系中最有可能发生。您

$this->Post->Page->find( all );

你们仍然有错误。

Answer 3

• 确保在邮政管理处装上页码模型(在任何职能之前应靠近控制器的顶端):

var $uses = array( Post ,  Page );

然后,你们应该能够发出公正的呼吁。

$this->Page->callthis();

Answer 4

我有同样的问题。

I have added the PluginName.ModelName, then it is resolved. So adding a PluginName in front of the plugin model is very good practice,

Thanks, Vijay

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