我有一个信标设计的Oracle数据库:许多表格都有相同的图象。 它们从一个庞大的桌子中重新 pieces,并随着时间的推移,将设立新的桌子。 当然,我没有获准进入庞大的桌子,只有小桌。 我如何有效地质疑这些表格?
很多人预先表示感谢。
我有一个信标设计的Oracle数据库:许多表格都有相同的图象。 它们从一个庞大的桌子中重新 pieces,并随着时间的推移,将设立新的桌子。 当然,我没有获准进入庞大的桌子,只有小桌。 我如何有效地质疑这些表格?
很多人预先表示感谢。
AFAIK,如果是你所说的的话,就没有办法对多个不同的表格使用一份单一的发言稿。 你们是否可以认为,所有表格都有联盟?
你们可以发挥编织职能,积极制定从所有相关表格中选取的LQ声明。
--Create tables. They can be created at any time, but they have
--to follow some sort of naming convention
create table temp1(test1 number, test2 varchar2(100));
create table temp2(test1 number, test2 varchar2(100));
create table temp3(test1 number, test2 varchar2(100));
--Create a package that will return one result at a time from all the tables.
create or replace package query_tables is
type output_rectype is record
(
test1 number
,test2 varchar2(100)
);
type output_rectype_table is table of output_rectype;
function query return output_rectype_table pipelined;
end query_tables;
/
create or replace package body query_tables is
function query return output_rectype_table pipelined is
sql_statement varchar2(32767);
output output_rectype;
my_cursor sys_refcursor;
begin
--Build a select statment that combines all relevant tables
for tables in (select table_name from user_tables where table_name like TEMP% ) loop
sql_statement := sql_statement || select * from ||tables.table_name|| union all ;
end loop;
--Remove the last union all
sql_statement := substr(sql_statement, 1, length(sql_statement) - 11);
--Get one result at a time and return it
open my_cursor for sql_statement;
loop
fetch my_cursor into output;
exit when my_cursor%notfound;
pipe row(output);
end loop;
end;
end query_tables;
/
--Insert some test data
insert into temp1 values(1, asdf );
insert into temp2 values(2, fgds );
insert into temp3 values(3, rewq );
--Display the results from all tables with one query
select * from table(query_tables.query);
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