我有<条码>TDictionary<TKeyClass,TValueClass>。
我想完成这样的事情。
for i := 0 to MyDictionary.Count -1 do
ShowMessage(MyDictionary.Keys[i].AStringProperty)
如果我完全知道他们的话,我再也无法接触钥匙。
唯一的选择是建立<条码>TDictionary<TValueClass, TKeyValue>? 因此,我可以 lo笑钥匙?
我发现,我的工作是建立一个<代码>。 TList<TKeyClass>,但情况并非如此。
利用一名统计员。
for Key in MyDictionary.Keys do
ShowMessage(Key.AStringProperty);
由于TDictionary是一片洗衣桌,你可以像一个阵列或TList那样,用惯性指数获取。 但是,一个统计员只做罚款。
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