Lisp s AppLY负责在名单上保留有计算依据的职能。 (摘自兰经评论)
例如,以下法典改动(清单1 2 3)至(+1 23)。
(apply # + (1 2 3))
然而,除了某些细小的差别外(投入作为图/清单提供),Zahurys的申请确实适用。
(defun add (x y) (+ x y)) (funcall # add 1 2) or (funcall # (lambda (x y) (+ x y)) 10 2)
apply(lambda x,y : x+y, [1,2])
你认为什么? Lisp s funrest和Adhurs之间是否有更大的差别?
难道有理由为什么斯图尔特选择这个名字,却不进行点名?
因为它是沙捞的,而不是LISP。 没有必要有相同的名称,fun calls<>t/code> 是LISP的指挥,apply是Salph中不同的。
apply is deprecated in-030, use the延用 syntax.
老年yn:
apply(foo, args, kwargs)
New syntax:
foo(*args, **kwargs)
在共同列席<代码>(第1号(清单2 3 4))中,与<代码>(fun 1 (清单2 3 4)完全相同,而<代码>(适用编号1 fun 1(清单2 3 4))则意味着根据 fun的大小而有所不同。
* (defun bleargh (a &rest b) (cons a b))
BLEARGH
* (funcall # bleargh 1 (list 1 2 3))
(1 (1 2 3))
* (apply # bleargh 1 (list 1 2 3))
(1 1 2 3)
因此,FUNCALL和APLY与过去一样,情况非常不同。
我看不出,为什么你要求Lisp sapply(<>>/code>将做任何与Sharma不同的事情。 这两项职能都具有职能和一份清单,然后将职能与清单要素作为理由。 ((+ 1 2 3)is an calls to +, with debate 1,2 and 3, isn t it?) 我看上去的是<条码> 适用 确实如此。
Lisp s和Ashhurc两种应用功能相同——鉴于功能 f和参数清单,p.适用于f。 唯一的区别是,沙尔的申请也接受关键词的词典。 在Lisp,这些内容将列入作为的参数清单:关键词论点。
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