我有以下数组：
[[499, 3], [502, 3], [502, 353], [499, 353]]
它们是一个矩形的顶点。
我需要找到左上角、右上角、左下角和右下角的顶点。
最好的python代码是什么？
谢谢
edit：感谢tokand指出这可以通过元组拆包来完成。
你可以分类。
(bottomleft, bottomright,topleft, topright) = sorted(vertices)
或者你可以用
corners.sort()
(bottomleft, bottomright,topleft, topright) = corners
# the unpacking here is redundant but demonstrative
作为参考，排序后的输出为：
>>> a = [[499, 3], [502, 3], [502, 353], [499, 353]]
>>> sorted(a)
[[499, 3], [499, 353], [502, 3], [502, 353]]
>>>
这将是O（nlogn），而肯定存在O（n）个可用的解。但对于这样大的列表，我不认为它有多大，除非你有很多，（在这种情况下，原生C实现的速度无论如何都会超过自定义python函数，所以从实际角度来看，它仍然是最佳的。）
vertices = [[499, 3], [499, 353], [502, 3], [502, 353]]
# if the origin is the top left
(topleft, bottomleft, topright, bottomright) = sorted(vertices)
# if the origin is the bottom left
(bottomleft, topleft, bottomright, topright) = sorted(vertices)
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