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如何获得Random号码[复制]
原标题:How to get Random Number [duplicate]
最佳回答

我一年前曾问过这个问题。

我认为,所选择的答案是精彩的。

问题回答

列出名单,从名单上删除:

List<int> numbers = Enumerable.Range(1, 100).ToList();

Random rnd = new Random();
List<int> picks = Enumerable.Range(1, 20).Select(n => {
  int index = rnd.Next(numbers.Count);
  int pick = numbers[index];
  numbers.RemoveAt(index);
  return pick;
});

这可能是解决这一问题的最简单方式,但它并非效率最高。 删除清单上的项目涉及移动下列项目。 有了更多的法典,你就可以避免这一举动,但就大多数而言,这部法典是足够的。





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