Question

I've got 2 变量:

period and result

我会怎样告诉Numpy溶剂(我假定我必须使用什么)来回 定期值,给我带来最高级成果? 期限为1至100。

Edit>:

Right now period at 14, gives me a result of 40 . period at 12 . gives me a result of 42 .

请允许我告诉大家,每一次都尝试<>定期。数值在1至100之间,结果只有最佳结果?

我猜测,我真的不需要这种假设,我很想知道这是否能够成为前进的道路。

Answer 1

仅宣布一个与第一个时期的数值相等的变量,然后由您自行选择,改变初始变量,只要现有数字更大:

biggest = period(0)
index = 0

for i in range (1, 100)
    if period(i) > biggest
         biggest = period(i)
         index = i

return biggest

Answer 2

I am not certain i understand the question, but if i do then NumPy indexing might be best:

period = NP.arange(50)
result = NP.random.randint(1, 101, 50)

q = NP.argmax(result)   # gives index of largest value in the result array
result[q]               # returns the highest value in the result array
period[q]               # returns the value of period corresponding to 
                        # the highest value for result

Answer 3

这并不明确你拥有哪些数据,但应当做到:

for period in periods:
    result = func(period)
    if result > resultmax:
        resultmax = result

or, if results is a numpy.array such that results[period] is the result from period, then simply

periodmax = results.argmax()

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