Question

我无法研究如何在XML档案中把产出与XML档案中的 que点分开,直到Xml档案中价值的那一天。

我的理解是,它将按当天的第一封信(s)进行分类,从而将星期五作为首批(因为其中的“F”)。但这不是我所希望的,而是应该按周日,即mon日、午餐日、午餐日、假日等顺序排列。

是否有办法将包含案文中日子的“日报”改为按时间分类?

我使用的法典如下:

 let obv = (string)query.Element("day")
 orderby obv 
 select new obv

Answer 1

页: 1 CulturalInfo.CurrentCulture.DateFormat.DayNames 阵容:

var daynames = Array.ConvertAll(
    CultureInfo.CurrentCulture.DateFormat.DayNames,
    d => d.ToUpperInvariant()
);

from ...
let obv = (string)query.Element("day")
orderby Array.IndexOf(daynames, obv.ToUpperInvariant())
select new obv

Answer 2

这使你可以任意安排一周的一天:

public class DayOfWeekComparer : IComparer<DayOfWeek>
{
    public static int Rank(DayOfWeek firstDayOfWeek, DayOfWeek x)
    {
        return (int)x + (x < firstDayOfWeek ? 7 : 0);
    }

    public static int Compare(DayOfWeek firstDayOfWeek, DayOfWeek x, DayOfWeek y)
    {
        return Rank(firstDayOfWeek, x).CompareTo(Rank(firstDayOfWeek, y));
    }

    DayOfWeek firstDayOfWeek;

    public DayOfWeekComparer(DayOfWeek firstDayOfWeek)
    {
        this.firstDayOfWeek = firstDayOfWeek;
    }

    public int Compare(DayOfWeek x, DayOfWeek y)
    {
        return DayOfWeekComparer.Compare(this.firstDayOfWeek, x, y);
    }
}

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