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读物的重复算法
原标题:Redundancy algorithm for reading noisy bitstream

我读了一条损失轨道流,我需要找到尽可能多可用数据的方法。 棕榈中有1个,0个,0个,但精度可能超过80%。

如果算法能够补偿许多分界线的缺失/缺失,则会给予奖金。

来源一米的读物与噪音相类似(通过公平贸易论坛使用麦克风),阅读时间可能因计算机速度而有所不同。

我记得三读光盘使用的算法? 层层,因此,使用几层层的电离层是一种很好的选择。 我不想忘记细节,这样,如果有人能够分享一些伟大的想法!

<><>Edit>: 补充抽样数据

Best case data:
 in: 0000010101000010110100101101100111000000100100101101100111000000100100001100000010000101110101001101100111000101110000001001111011001100110000001001100111011110110101011100111011000100110000001000010111
out: 0010101000010110100101101100111000000100100101101100111000000100100001100000010000101110101001101100111000101110000001001111011001100110000001001100111011110110101011100111011000100110000001000010111011

Bade case (timing is off, samples are missing):
out: 00101010000101101001011011001110000001001001011011001110000001001000011000000100001011101010011011001
 in: 00111101001011111110010010111111011110000010010000111000011101001101111110000110111011110111111111101

www.un.org/Depts/DGACM/index_spanish.htm Edit2: 我能够控制所发送的数据。 目前,试图进行简单的XOR检查(尽管它赢得了足够的打字)。

最佳回答
问题回答

There are lot of possibilities, see : http://en.wikipedia.org/wiki/Error_detection_and_correction

这可以帮助你改变轨道,但当你有所有轨道时,可能不适合检查。

最后,它可能只需要几条简单的法典。





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