Question

我想把地图分为一系列地图。例如,如果有一个有25个关键/价值乳制品的地图。我希望每个地图上有不超过10个元素的地图。

我怎么做呢?

我没有放弃一个解决办法,即有更好的粗体:

  static def splitMap(m, count){
    if (!m) return

    def keys = m.keySet().toList()
    def result = []
    def num = Math.ceil(m?.size() / count)
    (1..num).each {
      def min = (it - 1) * count
      def max = it * count > keys.size() ? keys.size() - 1 : it * count - 1
      result[it - 1] = [:]
      keys[min..max].each {k ->
        result[it - 1][k] = m[k]
      }
    }
    result
  }

m 地图。数量是地图内内容的最大数量。

Answer 1

。

Map.metaClass.partition = { size ->
  def rslt = delegate.inject( [ [:] ] ) { ret, elem ->
    ( ret.last() << elem ).size() >= size ? ret << [:] : ret
  }
  rslt.last() ? rslt : rslt[ 0..-2 ]
}

因此,如果你照此图:

def origMap = [1: a , 2: b , 3: c , 4: d , 5: e , 6: f ]

下列所有主张均通过:

assert [ [1: a ], [2: b ], [3: c ], [4: d ], [5: e ], [6: f ] ] == origMap.partition( 1 )
assert [ [1: a , 2: b ], [3: c , 4: d ], [5: e , 6: f ] ]       == origMap.partition( 2 )
assert [ [1: a , 2: b , 3: c ], [4: d , 5: e , 6: f ] ]         == origMap.partition( 3 )
assert [ [1: a , 2: b , 3: c , 4: d ], [5: e , 6: f ] ]         == origMap.partition( 4 )
assert [ [1: a , 2: b , 3: c , 4: d , 5: e ], [6: f ] ]         == origMap.partition( 5 )
assert [ [1: a , 2: b , 3: c , 4: d , 5: e , 6: f ] ]           == origMap.partition( 6 )

或作为<代码>Category (为避免在<代码>Map上添加任何内容:

class MapPartition {
  static List partition( Map delegate, int size ) {
    def rslt = delegate.inject( [ [:] ] ) { ret, elem ->
      ( ret.last() << elem ).size() >= size ? ret << [:] : ret
    }
    rslt.last() ? rslt : rslt[ 0..-2 ]
  }
}

然后,如果你需要这一功能,你可以简单地读到<条码>。 a. 同类:

use( MapPartition ) {
  assert [ [1: a ], [2: b ], [3: c ], [4: d ], [5: e ], [6: f ] ] == origMap.partition( 1 )
  assert [ [1: a , 2: b ], [3: c , 4: d ], [5: e , 6: f ] ]       == origMap.partition( 2 )
  assert [ [1: a , 2: b , 3: c ], [4: d , 5: e , 6: f ] ]         == origMap.partition( 3 )
  assert [ [1: a , 2: b , 3: c , 4: d ], [5: e , 6: f ] ]         == origMap.partition( 4 )
  assert [ [1: a , 2: b , 3: c , 4: d , 5: e ], [6: f ] ]         == origMap.partition( 5 )
  assert [ [1: a , 2: b , 3: c , 4: d , 5: e , 6: f ] ]           == origMap.partition( 6 )
}

友情链接