DisplayMetrics displaymetrics = new DisplayMetrics();
getWindowManager().getDefaultDisplay().getMetrics(displaymetrics);
height = displaymetrics.heightPixels;
width = displaymetrics.widthPixels;
Log.e("FirstImage", "Width = "+width+"Height = "+height);
以上是我用来显示屏幕尺寸的代码,但问题在于我正在读到width=3<20/code>和hels=569<>。 但是,我正在使用带有屏幕尺寸的摩托拉里程碑(<>编码>480x854)。
我如何能够找到正确的规模?
http://realmike.org/blog/2010/12/21/multiple-screen-sizes-with-processing-for-android/
以上链接拥有丰富的资源,可以说明屏幕分辨率和如何获得真正的屏幕分辨率等。
如果你不支持大型屏幕,那么你就会失去这种恐慌,因为屏幕往往较小,无法显示照片(这本来就是不支持你的大屏幕)。
如果你在你的发言中加上这一点,就会显示正确的价值观。
<supports-screens
android:largeScreens="true"
android:smallScreens="true"
android:normalScreens="true"
/>
你们甚至可能希望与你们一道发挥作用。
android:anyDensity
归责,但我并不认为需要解决你目前的问题。
审判
WindowManager wm = (WindowManager) getSystemService(Context.WINDOW_SERVICE);
Display d = wm.getDefaultDisplay();
int height = d.getHeight();
The <supports- Screens> tag should fin work. See See See
rel=“nofollow”http://developer.android.com/guide/topics/mani/supports- Screens-element.html
一个重要问题是,为什么你不相信你从显示台调机中重新获得的规模? 如果你们要做这样的事情的话。
canvas.drawRect(new Rect(0,0,width,height), new Paint());
Your rectangle would certainly fill the screen. There s a scaling happening, but maybe you don t care.
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