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当方法返回时,Google应用引擎deferred.dedeferre()失败
原标题:Google App Engine deferred.defer() failing when method returns

我正在尝试使用google.appengine.ext.deferred来运行一个Task。我正在将一个方法传递给defer()方法,该方法成功运行,但返回后会抛出ValueError:

  File ".../admin.py", line 73, in post
    result = deferred.defer(meeple_tasks.buildGames())
      File "/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/google/appengine/ext/deferred/deferred.py", line 198, in _curry_callable
        raise ValueError("obj must be callable")
    ValueError: obj must be callable

以下是我称之为defer的地方:

result = deferred.defer(meeple_tasks.buildGames())   

buildGames()将在完成时返回True。

最佳回答

您应该使用:

result = deferred.defer(meeple_tasks.buildGames)

如果使用buildGames(),则会立即调用函数,并将返回值传递给defer()。通过移除括号,可以将函数本身传递给defer。

问题回答

您需要这样调用您的延迟任务:

deferred.defer(meeple_tasks.buildGames)

“obj必须是可调用的”意味着(在您的情况下)值True是不可调用的。我是如何通过将buildGames方法调用插入队列并让AppEngine框架处理它,用“defer”编写对另一个进程(或任务)的延迟调用的。

请注意,不能返回任何带有延迟任务的内容。它们将在不同的进程上运行,可能在完全不同的服务器上运行。根据文件,他们是后台工作人员。





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